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Byju's Answer
Standard VII
Mathematics
Powers and Exponents
Solve the fol...
Question
Solve the following equation:
81
sin
2
x
+
81
cos
2
x
=
30
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Solution
81
sin
2
x
+
81
cos
2
x
=
30
⟹
81
sin
2
x
+
81
1
−
sin
2
x
=
30
(
81
sin
2
x
)
2
−
30
(
81
sin
2
x
)
+
81
=
0
⟹
81
sin
2
x
=
3
,
27
⟹
3
4
sin
2
x
=
3
,
3
3
sin
2
x
=
1
4
,
3
4
⟹
x
=
n
π
+
(
−
1
)
n
π
6
,
m
π
+
(
−
1
)
m
π
3
,
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1
Similar questions
Q.
The equation
81
sin
2
x
+
81
cos
2
x
=
30
has two roots in the
Q.
If
x
∈
[
0
,
2
π
]
, then the number of solutions of the equation
81
cos
2
x
+
81
sin
2
x
=
30
is
Q.
If the angles of a triangle
A
B
C
satisfy the equation
81
s
i
n
2
x
+
81
c
o
s
2
x
=
30
, then the triangle can be
Q.
The number of roots of the equation,
(
81
)
sin
2
x
+
(
81
)
cos
2
x
=
30
in the interval
[
0
,
π
]
is equal to:
Q.
If
x
ϵ
[
0
,
π
]
and
81
s
i
n
2
x
+
81
c
o
s
2
x
=
30
, then find number of values of
x
satisfy the given equation.
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