wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equation:
cos2x+22cosxsinx+1=0.

Open in App
Solution

cos2x+22sinxcosx+sin2x+cos2x=0
2cos2x+2sinxcosx+2sinxcosx+sin2x=0
2cosx(2cosx+sinx)+sinx(2cosx+sinx)=0
So, (2cosx+sinx)2=0
tanx=2,x=nπtan1(2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon