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Question

Solve the following equation:
cos(π2+5x)+sinx=2cos3x

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Solution

cos(π2+5x)+sinx=2cos3x
sin5x+sinx=2cos3x
2cos3xsin2x=2cos3x
Either, cos3x=0,3x=(2n+1)π2,x=(2n+1)π6.
or , sin2x=(1),2x=2nππ2,2x=nππ4.

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