CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equation:
cosx+cos4x+cos7x=0

Open in App
Solution

2cos4xcos3x+cos4x=0
cos4x(2cos3x+1)=0
So, cos4x=0,4x=(2n+1)π2,x=(2x+1)π8. and cos3x=12,3x=2nπ±π3,x=2nπ3±π9.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Expression formation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon