Question

Solve the following equation:
$\cos x+\sec x=2$

• A. $x=2n\pi$
• B. $x=n\pi$
• C. $x=-2n\pi$
• D. None of these

Answer 1

The correct option is A $x=2n\pi$

$\cos x+\sec x=2$

Put $\cos x=\frac{1}{\sec x},$ we get

${(\cos x-1)}^2=0\cos x=1,x=2n\pi$