Question

Solve the following equation:

$\frac{1}{3}(x-3)-x-3=2(x-1)$

• A. $-\frac{9}{4}$
• B. $-\frac{7}{4}$
• C. $-\frac{3}{4}$
• D. $-\frac{1}{4}$

Answer 1

The correct option is C $-\frac{3}{4}$

$\frac{1}{3}(x-3)-x-3=2(x-1)$
$=>\frac{x-3}{3}-x-3=2x-2$
$=>\frac{x-3-3x-9}{3}=2x-2$
$=>-2x-12=6x-6$
$=>-8x=6$
$=>x=-\frac{6}{8}$
$=>x=-\frac{3}{4}$