wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equation:
1+sinx+cosx+sin2x+cos2xtan2x=0

Open in App
Solution

1+sinx+cosx+2sinxcosx+2cos2x1=0
2cosx(sinx+cosx)+1(sinx+cosx)=0
(sinx+cosx)(2cosx+1)=0
tanx=1 and cosx=12
So, x=nππ4 and x=2nπ±2π3.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Angle and Its Measurement
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon