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Byju's Answer
Standard XII
Mathematics
Circular Measurement of Angle
Solve the fol...
Question
Solve the following equation:
1
+
sin
x
+
cos
x
+
sin
2
x
+
cos
2
x
tan
2
x
=
0
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Solution
1
+
sin
x
+
cos
x
+
2
sin
x
cos
x
+
2
cos
2
x
−
1
=
0
2
cos
x
(
sin
x
+
cos
x
)
+
1
(
sin
x
+
cos
x
)
=
0
(
sin
x
+
cos
x
)
(
2
cos
x
+
1
)
=
0
tan
x
=
−
1
and
cos
x
=
−
1
2
So,
x
=
n
π
−
π
4
and
x
=
2
n
π
±
2
π
3
.
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0
Similar questions
Q.
Solve the following equations.
sin
x
+
sin
2
x
+
sin
3
x
=
cos
x
+
cos
2
x
+
cos
3
x
.
Q.
Solve the following equations:
(i)
cos
x
+
cos
2
x
+
cos
3
x
=
0
(ii)
cos
x
+
cos
3
x
-
cos
2
x
=
0
(iii)
sin
x
+
sin
5
x
=
sin
3
x
(iv)
cos
x
cos
2
x
cos
3
x
=
1
4
(v)
cos
x
+
sin
x
=
cos
2
x
+
sin
2
x
(vi)
sin
x
+
sin
2
x
+
sin
3
=
0
(vii)
sin
x
+
sin
2
x
+
sin
3
x
+
sin
4
x
=
0
(viii)
sin
3
x
-
sin
x
=
4
cos
2
x
-
2
(ix)
sin
2
x
-
sin
4
x
+
sin
6
x
=
0
Q.
Solve the following equation:
sin
x
+
sin
2
x
+
cos
2
x
=
0
Q.
The equation
sin
2
x
+
cos
2
x
+
sin
x
+
cos
x
+
1
=
0
has no solution in:
Q.
Solve the following equation:
1
−
sin
2
x
=
cos
x
−
sin
x
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