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Question

Solve the following equation:
1+sinx+cosx+sin2x+cos2xtan2x=0

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Solution

1+sinx+cosx+2sinxcosx+2cos2x1=0
2cosx(sinx+cosx)+1(sinx+cosx)=0
(sinx+cosx)(2cosx+1)=0
tanx=1 and cosx=12
So, x=nππ4 and x=2nπ±2π3.

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