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Integration by Substitution

Solve the fol...

Question

Solve the following equation:
$\frac{1 + \sqrt{2 x + 1}}{x} = 1$

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Solution

$\frac{1 + \sqrt{2 x + 1}}{x} = 1 \sqrt{2 x + 1} = x - 1 2 x + 1 = {(x - 1)}^{2} 2 x + 1 = x^{2} - 2 x + 1 x^{2} - 4 x = 0 x (x - 4) = 0 x = 0, 4$

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