Solve the following equation- 2x-3-x2-2x-3 - 3x-5-x2-3x-5 x lies in -0- 2-If true then enter 1 and if false then enter 0

Given, #160; 2x 3 x^ 2 2x+3 #160;= 3x 5 x^ 2 3x+5 , On cross multiplying we get, ∴ (x^ 2 2x+3)(3x 5) = (2x 3)(x^ 2 3x+5) 3x ^ 3 11x^ 2 ...

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Solve the fol...

Question

Solve the following equation:
$\frac{2 x - 3}{x^{2} - 2 x + 3} = \frac{3 x - 5}{x^{2} - 3 x + 5}$ $x$ lies in $[0, 2]$
If true then enter $1$ and if false then enter $0$

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