Question

Solve the following equation:
$\frac{3}{2^{\log x}}=\frac{1}{64}$

Answer 1

$\frac{3}{2^{logx}}=\frac{1}{64}\Rightarrow 2^{logx}=\left(3\right).64\Rightarrow logx={log}_{2}3+6\Rightarrow x=\left({10}^{lo{g}_{2}3}\right){10}^6\Rightarrow x={10}^6\left({10}^{lo{g}_{2}3}\right).$