Question

Solve the following equation:

$\frac{4}{5}(x+\frac{5}{6})+\frac{2}{3}(x-\frac{1}{4})=1\frac{1}{9}$

• A. $\frac{5}{19}$
• B. $\frac{5}{16}$
• C. $\frac{5}{14}$
• D. $\frac{5}{12}$

Answer 1

Answer: (D)

$\frac{5}{12}$

$\frac{4}{5}(x+\frac{5}{6})+\frac{2}{3}(x-\frac{1}{4})=1\frac{1}{9}$
$=>\frac{4x}{5}+\frac{20}{30}+\frac{2x}{3}-\frac{2}{12}=\frac{10}{9}$
$=>\frac{4x}{5}+\frac{2}{3}+\frac{2x}{3}-\frac{1}{6}-\frac{10}{9}=0$
$=>\frac{72x+60+60x-15-100}{90}=0$
$=>72x+60x=-60+15+100$
$=>132x=55$
$=>x=\frac{55}{132}$
$=>x=\frac{5}{12}$