Question

Solve the following equation:
$\frac{4}{\sqrt[3]{3x}+2}+\frac{\sqrt[3]{3x}+3}{5}=2$

Answer 1

let$x^{1/3}=y$ and $x\ne -8$

$⟹20+y^2+5y+6=10y+20$

$y^2-5y+6=0⟹y=3,2$

$⟹x=27,8$