Question

Solve the following equation:
${\left(\frac{4}{9}\right)}^{\sqrt{x}}=(2.25{)}^{\sqrt{x}-4}$

Answer 1

$(\frac{4}{9}{)}^{\sqrt{x}}=(2.25{)}^{\sqrt{x}-4}$

$(\frac{9}{4}{)}^{-\sqrt{x}}=(\frac{9}{4}{)}^{\sqrt{x}-4}$

$⟹-\sqrt{x}=\sqrt{x}-4⟹\sqrt{x}=2⟹x=4$