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Question

Solve the following equation.
log2(4x+4)=log22x+log2(2x+13)

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Solution

log2(4x+4)=log22x+log2(2x+13)(4x+4)=2x(2x+13)4x3.2x4=0

But 2x cannot be <0.
Therefore, 2x=4x=2.

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