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Question

Solve the following equation:
sinx+sin2x+sin3x=0

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Solution

sinx+sin2x+sin3x=0
2sin2xcosx+sin2x=0
sin2x(2cosx+1)=0
either, sin2x=0
2x=nπ,x=nπ2.
or, cosx=12
x=2nπ±2π3.

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