CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equation:
sinxsin2x+sin5x+sin8x=0.

Open in App
Solution

sinxsin2x+sin5x+sin8x=0
2sin3xcos2x+2cos5xsin3x=0
2sin3x(cos2x+cos5x)=0
sin3xcos7x2cos3x2=0
So, sin3x=0, cos7x2=0 and cos3x2=0.
x=nx3,x=(2n+1)π7,x=(2n+1)π3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Compound Angles
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon