MyQuestionIcon

2

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Rational Expression

Solve the fol...

Question

Solve the following equation:
$\sqrt[3]{16 - x^{3}} = 4 - x$

Open in App

Solution

$\sqrt[3]{16 - x^{3}} = 4 - x 16 - x^{3} = {(4 - x)}^{3} 16 - x^{3} = 64 - 48 x + 12 x^{2} - x^{3} 12 x^{2} - 48 x + 48 = 0 x^{2} - 4 x + 4 = 0 {(x - 2)}^{2} = 0 x = 2$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Solve the following cubic equation :

x^{3} + x^{2} - 16 x = 16

Q. Solve the following equation:

\frac{log (35 - x^{3})}{log (5 - x)} = 3

Q. Solve the following equations:

\frac{x^{3} + y^{3}}{(x + y)^{2}} + \frac{x^{3} - y^{3}}{(x - y)^{2}} = \frac{43 x}{8}, 5 x - 7 y = 4

Q. Solve the following equation:

log (3^{x} - 2^{4 - x}) = 2 + \frac{1}{4} log 16 - \frac{x log 4}{2}

Q. Solve the following equation.

16 = 4 + 3 (t + 2)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Appendicular Skeleton

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Rational Expression

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon