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Solving Using Quadratic Formula When D>0

Solve the fol...

Question

Solve the following equation:
$\sqrt{37 - x^{2}} + 5 = x$

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Solution

$\sqrt{37 - x^{2}} + 5 = x \sqrt{37 - x^{2}} = (x - 5) 37 - x^{2} = x^{2} - 10 x + 25 2 x^{2} - 10 x - 12 = 0 x^{2} - 5 x - 6 = 0 (x - 6) (x + 1) = 0 x = - 1, 6$

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