Solve the following equation- -3x - x2 - 5 - 2x - 6

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Integration by Substitution

Solve the fol...

Question

Solve the following equation:
$\sqrt{3 x - x^{2} - 5} = 2 x - 6$

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\frac{2 x - 3}{x^{2} - 2 x + 3} = \frac{3 x - 5}{x^{2} - 3 x + 5}

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\frac{x^{2} - 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{x^{2} + 12 x + 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

(x^{2} + x + 1) + (x^{2} + 2 x + 3) + (x^{2} + 3 x + 5) + \dots \dots + (x^{2} + 20 x + 39) = 4500.

\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

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