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Solving Using Quadratic Formula When D>0

Solve the fol...

Question

Solve the following equation:
$\sqrt{6 - 4 x - x^{2}} = x + 4$

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Solution

$\sqrt{6 - 4 x - x^{2}} = x + 4 6 - 4 x - x^{2} = {(x + 4)}^{2} 6 - 4 x - x^{2} = x^{2} + 8 x + 16 2 x^{2} - 12 x + 10 = 0 x^{2} - 6 x + 5 = 0 (x - 5) (x - 1) = 0 x = 1, 5$

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