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Byju's Answer
Standard VI
Mathematics
Formation of Algebraic Expressions
Solve the fol...
Question
Solve the following equation:
√
2
x
+
1
x
−
1
−
2
√
x
−
1
2
x
+
1
=
1
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Solution
√
2
x
+
1
x
−
1
b
e
t
t
−
2
t
=
1
t
2
−
t
−
2
=
0
(
t
−
2
)
(
t
−
1
)
=
0
t
=
−
1
,
2
√
2
x
+
1
x
−
1
=
−
1
2
x
+
1
x
−
1
=
1
2
x
+
1
=
x
−
1
x
=
−
2
√
2
x
+
1
x
−
1
=
2
2
x
+
1
x
−
1
=
4
2
x
+
1
=
4
x
−
4
x
=
5
2
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