wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Solve the following equation:
x+1+4x+13=3x+12

Open in App
Solution

x+1+4x+13=3x+12
squaring both sides
x+1+4x+13+2x+14x+13=3x+12
2x+13x+13=3x+125x14=2x2
2x+14x+13=2(x+1)
squaring both sides
(x+1)(4x+13)=(x+1)2=x2+1+2x
4x2+4x+13+13x=x2+2x+1
3x2+15x+12=0
x2+5x+4=0
x2+4x+x+4=0
x(x+4)+(x+4)=0
(x+4)+(x+4)=0
x=1,4
Hence, the answer is 1,4.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integration by Substitution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon