Question

Solve the following equation for $0^o<\theta <{90}^o$ :

$2\sin 2\theta =\sqrt{3}$

Answer 1

$2\sin 2\theta =\sqrt{3}$

$\sin 2\theta =\frac{\sqrt{3}}{2}$

$\sin 2\theta =\sin {60}^o$

$2\theta ={60}^o$

$\theta ={30}^o$