Solve the following equation for $x$ .
$3 (2 x + 1) + 2 (3 x + 1) = 17$

1

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- 1

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\frac{1}{2}

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2

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Solution

The correct option is A $1$
Given, $3 (2 x + 1) + 2 (3 x + 1) = 17$
$\Rightarrow 6 x + 3 + 6 x + 2 = 17$
$\Rightarrow 12 x = 12$
$\Rightarrow x = 1$

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