Solve the following equation for x:
2x+35−10=4−3x2.
Given, 2x+35−10=4−3x2
⇒2x+3−505=4−3x2 …[Cross-multiplying the denominators on the LHS]
⇒2x−475=4−3x2
⇒2(2x−47)=5(4−3x) …[Cross-multiplying the denominators]
⇒4x−94=20−15x.
Transposing x terms to one side, we get,
⇒4x+15x=20+94
⇒19x=114
⇒x=6.
Hence, option D is correct.