(15+4√14)t+(15−4√14)t=30 ....(1)
Here, (15+4√14)(15−4√14)=1
(15−4√14)=1(15+4√14)
Using this in eqn (1), we get
(15+4√14)t+(115+4√14)t=30
Put (15+4√14)t=u
⇒u2−30u+1=0
⇒u=15±4√14
⇒(15+4√14)t=15±4√14
⇒t=1,−1
⇒x2−2|x|=1;x2−2|x|=−1
Now, if x≥0
⇒x2−2x−1=0 ; x2−2x+1=0
⇒x=1±√2 ; x=1
∴x=1+√2;x=1
Now, if x<0
x2+2x−1=0;x2+2x+1=0
⇒x=−1±√2 ; x=−1
∴x=−1−√2;x=−1
So, the number of roots of the eqn are 4