Question

Solve the following equation for x :

$\sqrt{(\frac{3}{5}{)}^{1-2x}}=4\frac{17}{27}$

Answer 1

$\sqrt{(\frac{3}{5}{)}^{1-2x}}=4\frac{17}{27}$

$\left[\right(\frac{3}{5}{)}^{1-2x}{]}^{1/2}=\frac{125}{27}$

$(\frac{3}{5}{)}^{\frac{1-2x}{2}}=(\frac{5}{3}{)}^3$

$\frac{1-2x}{2}=-3$

$1-2x=-6$

$2x=7$

$x=\frac{7}{2}$