Solve the following equation:
2a3-5=3
Find the value of a
We have, 2a3-5=3
⇒2a3-5=3⇒2a3=3+5[Transposing5toRHS]⇒2a3=8⇒a=8×32[Transposing23toRHS]⇒a=12
Hence, a=12 is the solution of the given equation.
Solve the following equation:5(2x−3)−3(3x−7)=5
y3+3=5
Solve the following equation
2b3-5=3