Question

Solve the following equation :

$\frac{4(y+2)}{5}=7+\frac{5y}{13}$

Answer 1

$\frac{4(y+2)}{5}=7+\frac{5y}{13}\Rightarrow \frac{4y+8}{5}=\frac{91+5y}{13}\text{by cross multiplying}\Rightarrow 13(4y+8)=5(91+5y)\Rightarrow 52y+104=455+25y\Rightarrow 52y-25y=455-104\Rightarrow 27y=351\Rightarrow y=\frac{351}{27}\Rightarrow y=13$