Question

Solve the following equation.
i) $10P+10=100$
ii) $12P-5=25$
iii) $2(x+4)=12$

• A. (i) $P=9$ (ii) $P=\frac{5}{3}$ (iii) $x=2$
• B. (i) $P=19$ (ii) $P=\frac{5}{3}$ (iii) $x=3$
• C. (i) $P=9$ (ii) $P=\frac{5}{2}$ (iii) $x=2$
• D. None

Answer 1

Answer: (C)

(i) $P=9$ (ii) $P=\frac{5}{2}$ (iii) $x=2$

(1)

$10P+10=100$

$10P=100-10$

$10P=90$

$P=\frac{90}{10}=9$

(2)

$12P-5=25$

$12P=25+5$

$12P=30$

$P=\frac{30}{12}=\frac{5}{2}$

(3)

$2(x+4)=12$

$x+4=\frac{12}{2}$

$x+4=6$

$x=6-4$

$x=2$