Solve the following equation sin - - sin 2-

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Standard XII

Mathematics

Trigonometric Ratios of Multiple of an Angle

Solve the fol...

Question

Solve the following equation
$sin α = sin 2 α .$

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Solution

$sin α - 2 cos α sin α = 0$
$sin α (1 - 2 cos α) = 0$
$sin α = 0$ or $2 cos (α) - 1 = 0$
$α = 2 π n$ and or $cos α = \frac{1}{2}$
$α = π + 2 π n$ or $α = \frac{π}{3} + 2 π n$ , and $α = \frac{4 π}{3} + 2 π n$
Solution: $x = 2 π n, x = π + 2 π n, x = \frac{π}{3} + 2 π n, x = \frac{4 π}{3} + 2 π n$ .

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Solve the following equationsinα=sin2α.

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Solve the following equation
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