Question

Solve the following equation $\sqrt{3}{x}^2-\sqrt{2}x+3\sqrt{3}=0$.

Answer 1

$\sqrt{3x^2}-\sqrt{2x}+3\sqrt{3}=0weknowthat\Rightarrow D=b^2-4ac\Rightarrow D=\left(-\sqrt{2}\right)=4\times \sqrt{3}\times 3\sqrt{3}\Rightarrow 2-12=-10then,roots=\frac{-\sqrt{3}\pm \sqrt{-10}}{2\times \sqrt{3}}\Rightarrow \frac{\sqrt{3}\pm \sqrt{10i}}{2\sqrt{3}}roots=\frac{\left(\sqrt{10i}+\sqrt{3}\right)}{2\sqrt{3}}and\frac{\left(\sqrt{3}-\sqrt{10i}\right)}{2\sqrt{3}}$