Solve the following equation. t−(2t+5)−5(1−2t)=2(3+4t)−3(t−4).
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Solution
t−(2t+5)−5(1−2t)=2(3+4t)−3(t−4) ⇒t−2t−5−5+10t=6+8t−3t+12 [Using distributive property] ⇒9t−10=5t+18 [Combining like terms] ⇒9t−5t=18+10 [Transposed 5t and −10 to other side] ⇒9t−5t=28 ⇒4t=28 ⇒t=284 [Transposed 4 to other side] ⇒t=7