Question

Solve the following equation using the general formula:
$x^2-3x-2=0$

Answer 1

$x^2-3x-2=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-(-3)\pm \sqrt{(-3{)}^2-4\times (-2)\times 1}}{2\times 1}=\frac{3\pm \sqrt{1}}{2}=\frac{3\pm 1}{2}$

$\therefore x=2,1$.