Question

Solve the following equation using the general formula:
$x^2+5x-1=0$

Answer 1

$x^2+5x-1=0$

$x=dfrac-b\pm \sqrt{b^2-4ac}2a=\frac{-5\pm \sqrt{25-4\times (-1)\times 1}}{2\times 1}=\frac{-5\pm \sqrt{29}}{2}$

$x=\frac{-5+\sqrt{29}}{2},\frac{-5-\sqrt{29}}{2}$.