Question

Solve the following equation using the trial and error method.
11+2x=19

Answer 1

Putting\quad =0

$11+2x=19$

$11+(2\times 0)=0$

It is not true.

Putting\quad $x=1$

$11+2x=19$

$11+(2\times 1)=13$

It is not true.

Putting\quad $x=2$

$11+2x=19$

$11+(2\times 2)=15$

It is not true.

Putting\quad $x=3$

$11+2x=19$

$11+(2\times 3)=17$

It is not true.

Putting\quad $x=4$

$11+2x=19$

$11+(2\times 4)=19$

Its a true solution.