Question

Solve the following equation using the trial and error method.
$2x+4=8$

Answer 1

Putting $x=0$

$2x+4=8$

$(2\times 0)+4=4$

It is not true.

Putting $x=1$

$2x+4=8$

$(2\times 1)+4=6$

It is not true.

Putting$x=2$

$2x+4=8$\\

$(2\times 2)+4=8$

It is true solution.