Question

Solve the following equation using the trial and error method.
$\frac{12}{m}=3$

Answer 1

When m=0

$\frac{12}{3}=m$

$\frac{12}{3}=0$

It is not true solution.

When m=1

$\frac{12}{3}=m$

$\frac{12}{3}=1$

It is not true solution.

When m=2

$\frac{12}{3}=m$

$\frac{12}{3}=2$

It is not true solution.

When m=3

$\frac{12}{3}=m$

$\frac{12}{3}=3$

It is not true solution.

When m=4

$\frac{12}{3}=m$

$\frac{12}{3}=4$

It is the true solution.