Solve the following equation:
zz+15=49
Find the value of z
zz+15=49⇒9z=4(z+15)[Crossmultiplication]⇒9z=4z+60
Rearranging the equation and combining like terms, we get
⇒9z–4z=60⇒5z=60⇒z=605⇒z=12
Hence, z=12 is the solution of given equation.