Question

Solve the following equations.
(1) $y-5$ = 1 (2) 8 = t + 5 (3) 4x = 52 (4) 19 = $m-$4
(5) $\frac{P}{4}=9$ (6) x + 10 = 5 (7) $m-5=-12$ (8) p + 4 = $-$ 1

Answer 1

(1)
y − 5 = 1

⇒ y − 5 + 5 = 1 + 5 (Add 5 to both sides)

⇒ y + 0 = 6

⇒ y = 6

Thus, the solution of the given equation is y = 6.

(2)
8 = t + 5

⇒ 8 − 5 = t + 5 − 5 (Subtract 5 from both sides)

⇒ 3 = t + 0

⇒ 3 = t

Thus, the solution of the given equation is t = 3.

(3)
4x = 52

⇒ $\frac{4x}{4}=\frac{52}{4}$ (Divide both sides by 4)

⇒ x = 13

Thus, the solution of the given equation is x = 13.

(4)
19 = m − 4

⇒ 19 + 4 = m − 4 + 4 (Add 4 to both sides)

⇒ 23 = m + 0

⇒ 23 = m

Thus, the solution of the given equation is m = 23.

(5)
$\frac{p}{4}=9$

⇒ $\frac{p}{4}\times 4=9\times 4$ (Multiply both sides by 4)

⇒ p = 36

Thus, the solution of the given equation is p = 36.

(6)
x + 10 = 5

⇒ x + 10 − 10 = 5 − 10 (Subtract 10 from both sides)

⇒ x + 0 = −5

⇒ x = −5

Thus, the solution of the given equation is x = −5.

(7)
m − 5 = −12

⇒ m − 5 + 5 = −12 + 5 (Add 5 to both sides)

⇒ m + 0 = −7

⇒ m = −7

Thus, the solution of the given equation is m = −7.

(8)
p + 4 = −1

⇒ p + 4 − 4 = −1 − 4 (Subtract 4 from both sides)

⇒ p + 0 = −5

⇒ p = −5

Thus, the solution of the given equation is p = −5.