Solve the following equations.
$2^{x} + 3^{y} = 17, 2^{x + 2} - 3^{y + 1} = 5$ .

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Solution

$2^{x} + 3^{y} = 17$
$17 = 2^{3} + 3^{2}$
So, x = 3 and y = 2
Substituting the value in the other equation $2^{x + 2} - 3^{y + 1}$ =5
$2^{5} - 3^{3}$ = 32-27 = 5 = RHS
Hence, x = 3 and y = 2

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