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Question

Solve the following equations:
2x3+3x2+3x+1=0.

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Solution

Given equation, 2x3+3x2+3x+1=0

2x3+2x2+x2+2x+x+1=0(2x+1)(x2+x+1)=0

Solving the 2 equations, we have x=12,1±3i2


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