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Question

Solve the following equations:
4x3y=1,
12xy+13y2=25.

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Solution

4x3y=14x=3y+1.....(i)

12xy+13y2=25

(4x)3y+13y2=25

Substituting (i)
(3y+1)3y+13y2=25

9y2+3y+13y2=25

22y2+3y25=0

22y222y+25y25=0

22y(y1)+25(y1)=0
(22y+25)(y1)=0

y=2522,1

Substituting y in (i)
4x=3(2522)+1

x=5388

4x=3(1)+1

x=1

x=5388,1

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