6√x=5x−12−136√x=5√x−13
Put √x=t
6t=5t−136t2+13t−5=06t2−2t+15t−5=02t(3t−1)+5(3t−1)=0(2t+5)(3t−1)=0t=−52,13√x=tx=t2x=(−52)2,(13)2x=254,19
Solve each of the following equation:
(x2+5x+4)(x2+5x+6)=120