Question

Solve the following equation:
$9\frac{1}{4}=y-1\frac{1}{3}$

Answer 1

Given:

$\Rightarrow 9\frac{1}{4}=y-1\frac{1}{3}$

$\Rightarrow \frac{37}{4}=y-\frac{4}{3}$

$\Rightarrow y=\frac{37}{4}+\frac{4}{3}$

Here, LCM of $4,3$ is $12$.

$\Rightarrow y=\frac{111+16}{12}$

$\Rightarrow y=\frac{127}{12}$

$\therefore y=10\frac{7}{12}$