Question

Solve the following equations:
$a^x=c{b}^x$.

Answer 1

$a^x=c{b}^x$

Applying $\log$ on both the sides, we get

$\log \left(a^x\right)=\log \left(c{b}^x\right)\Rightarrow x\log a=\log c+x\log b\Rightarrow x(\log a-\log b)=\log c\Rightarrow x=\frac{\log c}{\log a-\log b}$