Solve the following equations and check your result.
$2 y + \frac{5}{3} = \frac{26}{3} - y$

y = \frac{9}{2}

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y = \frac{7}{3}

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y = \frac{7}{2}

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y = \frac{1}{2}

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Solution

The correct option is B $y = \frac{7}{3}$
$G i v e n, 2 y + \frac{5}{3} = \frac{26}{3} - y \Rightarrow 2 y + y = \frac{26}{3} - \frac{5}{3} [T r a n s p o s i n g - y t o L H S a n d \frac{5}{3} t o R H S] \Rightarrow 3 y = \frac{21}{3} [B y t a k i n g L C M o n R H S] \Rightarrow 3 y = 7 \Rightarrow \frac{3 y}{3} = \frac{7}{3} [D i v i d i n g b o t h s i d e s b y 3] \Rightarrow y = \frac{7}{3}$

Check:
LHS = $2 y + \frac{5}{3} = 2 \times \frac{7}{3} + \frac{5}{3} = \frac{14}{3} + \frac{5}{3} = \frac{19}{3}$
RHS = $\frac{26}{3} - y = \frac{26}{3} - \frac{7}{3} = \frac{19}{3}$
Clearly, LHS = RHS
Hence checked!!

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