Question

Solve the following equations and check your results. If $2y+\frac{5}{3}=\frac{26}{3}-y$ and $y=\frac{7}{m}$, then $m$ is equal to

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

Answer: (D)

$3$

Given, $2y+\frac{5}{3}=\frac{26}{3}-y$ ....(1)

and $y=\frac{7}{m}$ ....(2)

Substitute this value of $y$ in equation (1), we get

$2\left(\frac{7}{m}\right)+\frac{5}{3}=\frac{26}{3}-\frac{7}{m}$

Bring like terms together,

$\frac{14}{m}+\frac{7}{m}=\frac{26}{3}-\frac{5}{3}$

$\Rightarrow \frac{14+7}{m}=\frac{26-5}{3}$

$\Rightarrow 21m=21\times 3$

$\Rightarrow m=3$