Question

Solve the following equations and check your results. If $4z+3=6+2z$ and $z=\frac{3}{m}$, then $m$ is equal to

• A. $12$
• B. $4$
• C. $2$
• D. $13$

Answer 1

The correct option is C $2$

Given, $4z+3=6+2z$

We need to find $z$ in terms of $z=\frac{3}{m}$

$\therefore 4z-2z=6-3$ .... Bringing $z$ to one side and constants to other side

$\therefore 2z=3$

$\therefore z=\frac{3}{2}$

Comparing this with $z=\frac{3}{m}$, we get

$m=2$