Solve the following equations and verify your answer :
2x−(7−5x)9x−(3+4x)=76
2x−(7−5x)9x−(3+4x)=76⇒2x−7+5x9x−3−4x=76⇒7x−75x−3=76
By cross multiplication :
6(7x−7)=7(5x−3)⇒42x−42=35x−21⇒42x−35x=−21+42⇒7x=21⇒x=217=3∴x=3
Verification :
L.H.S.=2x−(7−5x)9x−(3+4x)=2×3−(7−5×3)9×3−(3+4×3)=6−(7−15)27−(3+12)=6−7+1527−3−12=1412
=76 = R.H.S.